Mathematical Puzzle – No. Seven

Solve this puzzle. It is easy if you use some logic.

If a number AABB is divided by another number AB, the quotient is BB and the remainder is AA. If A and B represent single digits, can you find the digits? If you find the answer send me a comment, please.

SOLUTION TO PUZZLE # 6

Let the cost of an apple be \$ x, that of an orange be \$ y and of a mango be \$ z.

Cost of three apples and an orange is as much as the cost of two mangoes, therefore,

3x + y = 2z

or  3x + y – 2z + 0…..(I)

Also, one apple, two oranges and three mangoes together cost \$ 25, therefore,

x + 2y + 3z = 25…….(II)

To eliminate z from the equations we multiply (I) by 3 and (II) by 2 and then add them. Thus, we get

11x + 7y = 50………..(III)

Since x and y both have integral values, by trial and error we get x = 2 and y = 4. Putting these values in (II) we get z = 5.

Answer: The cost of an apple is \$ 2, an orange is \$ 4 and a mango is \$ 5.

Congratulations to Mr. Kishore for correct answer.

0
Liked it
No Responses to “Mathematical Puzzle – No. Seven”
Post Comment