A lab determining the solubility of Sodium chloride in water at room temperature.
This experiment is designed to determine the solubility of Sodium Chloride (NaCl) in water at room temperature. You can determine this by taking a set amount of the solution, 10 ml, and heating it so that all the water evaporates leaving behind the NaCl.
Determine how much NaCl was in the water by weighing it before heating and after heating so that it is possible to calculate the solubility of salt. The solubility will approximately be 35g/100ml if the temperature is 19°. The final result was 40g/100ml which is a fair calculation.
Purpose:The purpose of this lab was to determine the solubility of Sodium Chloride (NaCl) in water at room temperature.
|Test 1||Test 2||Test 3|
|Beaker and Solution Mass||121.69g||N/A||N/A|
|Beaker after Heating||112.01g||111.99g||111.99g|
Mass of NaCl = (Beaker Mass – Beaker after Heating) x 100
Mass of NaCl = (111.59 – 111.99) x 100
Mass of NaCl = 40
Solubility = 40g/100ml
c) The evidence according to experimental design, materials, procedure, and skills is fairly conclusive. The only flaw would be that we did not use pipet’s to obtain 10ml of the required solution, instead we used graduated cylinders which aren’t quite as accurate as the pipet.
d) The answer that was obtained is fairly accurate but the accuracy could have still been higher.
e) The percentage difference is 11%.
Conclusion: The purpose of this experiment was to determine the solubility of Sodium Chloride and it was determined that it was 40g/100ml which is fairly close to the published data.
Sources of Experimental Error:
- No cover on beaker so some NaCl could have escaped with the water
- Solution making may not have been accurate
- Pipet not used therefore solution amount may have been off minutely